l-6. plk This lemma can be found in [lo]. Now we prove Theorem 3. Let r denote a positive integer for which r aro( I, i ). We evidently have x(kP,,6i-I)( i=l = k6,0)( f IA(P,,6i)I + ” f lA(Pr,6i+5)/) + &6,1)( + ’ ’ ‘+ k6,4)1 -tw(6,5)~+~ + k6,5)+fw+S2 2 >-n-2+ 3 ;ir. Hence there exists an io for which &P,,6io--l)l + /A(P,,6io)l + . ” + &P,,6io+5)1 2 -n+4n-2 > 3 2 pi 6 4n = 7 r + 3&$ r - F. r (14) Clearly for every u n lL4P,,u)l ~$ for all i= 1,2,3. G. N. &irk&y/ Discrete Mathematics 202 (1999) 227-238 235 In that case (15) and (18) imply that there exist integers ~1,. . . ,245 such that Odu, < ... ~$ since otherwise &P,,6io)l + . . r + 2: f =4$ + sp + 4 r I r with (18). which would hold in contradiction From (19) it follows that the sequence (6io +ul , . . . , 6io + US} contains a subsequence erms which are pairwise relatively prime, proving our claim in this {jl,jZ,j3} of 3 t case. (p,,6io+5)( < z $ is similar. Thus now we may assume that The case when (A In this case we choose ji = 6i0 - 1 and j3 = 6io + 5. For j2 we choose one from the integers 6i0 + 1,6ie -t- 2 and 6io + 3 for which (there must be one such a j2) and then (16) and (17) clearly hold. Thus the claim is proved, we have jl, j2 and j3 satisfying (16) and (17). Let a denote a positive integer for which a~A(p,,j,) and l-I Pb P’r (1-i) >l-;. (20) Lemma 3 and the choice of r guarantee that such an a exists. We are going to estimate from below the number of solutions b of (a,b)= 1, b EA(P,,jz). (21) Assume that pl(a,d) for some d z jZ(modP,). Since (jr,j,)= 1 we clearly have p > r. Denote by h(F’,., j,z) the number of those integers d for which d 1 - $ <2w(“)<22*. 236 G. N. &irk&y I Discrete Mathematics 202 (1999) 227-238 From this and (20) we get for large n > n - 2210glogn > n. ( ” > ( B > 8 Pr 1 - 1 - log n 4 p, (22) Denoting the number of solutions of (21) by X, we have by (17) and (22) (23) Therefore using Lemma 3 there are at least (~/20)(n/P,) and integers b satisfying (21) l-I p>, db (1 -J-) > (I-;). (24) Let us denote the set of these integers by B. We have We denote by F the set of integers f E AcP,,jj). Again we define a bipartite graph G” between B and F as follows: We have an edge between a b E B and an f E F if and only if (ab, f) = 1. or an arbitrary b E B. Put E = {ab 1 b E B} and let us Next we estimate (Np(b)j f take an e=abEE. From (16), if g = js(modP,) and p)(e,g), then p>r. Again we have G.N. Shrk6zy I Discrete Mathematics 202 (1999) 227-238 231 We obtain from this, (20) and (24) for large enough n that h(P,., j,,e) > k n (1 - $) dr - Z4s p>r =;-J a P>r (*_$_) 5 (I-g-24* P’? > ( > l--- E2\"_24*> 8 Pr ( > 1-E 14_ 4 P,’ (26) Eqs. (17) and (26) yield that (27) Claim 2. K( I, 1) c G”. Proof of Claim. Using (4), (15), (25) and (27) we get (28) Here we also have I{fEF(deg(f)>l}l since otherwise IE(G”)l$~IBI a$!, +lFlZ<)BI;;, Y (29) a contradiction with (27). To find a lower bound on the number of subsets of B of size 1 with a common neighbor in F, we use Jensen’s inequality, (15), (28) and (29) to obtain ftF 238 G.N. Shrkiizy I Discrete Mathematics 202 (1999) 227-238 However, using (15) there are only (i;j)< (AY)‘< (22) subsets of B of size 1. Hence, there must be a B’ c B such that JB’I=Z and where we used (4), (17) and the fact that c3 is sufficiently small. Denote the elements of B’ by bl , b2, . . . , bl and choose 1 integers f~, f2, . . . , fl from NG” (B’). Then G(‘%, 1..., b&./i 1...,. h) the proof of the claim. By adding a we get the desired is a K(1, I) in G” completing K(l,Z,Z) in G(A). References [l] R. Ahlswede, L.H. Khachatrian, On extremal sets without coprimes, Acta Arith. 66 (1994) -99. [2] R. Ahlswede, L.H. 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